PHY301 Assignment no 2 fall 2016
Here is the Complete PHY301 Assignment No 1 Solution and Discussion. PHY301 Assignment Due Date is : December 09, 2016.
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PHY301 Assignment no 2
Semester Fall 2016
Circuit Theory - Phy301
Assignment Marks: 20
Assignment Due Date: December 09, 2016
V2-V1=6
Circuit Theory - Phy301
Assignment Marks: 20
Assignment Due Date: December 09, 2016
PHY301 Assignment Important instructions:
- To solve this assignment, you should have good command over first 18 lectures.
- Upload assignments properly through LMS, (No Assignment will be accepted through email).
- Write your ID on the top of your solution file.
- All students are directed to use the font and style of text as is used in this document.
- Don’t use colorful back grounds in your solution files.
- Use Math Type or Equation Editor etc for mathematical symbols.
- You can draw/Label circuit diagrams in “Paint”, “Corel Draw” or in circuit maker or in any convenient software. The simple and easy way is to copy the given image in Paint and do the required changes in it.
PHY301 Assignment Question no 1:
Use Nodal analysis to find I1 in the network given below. Identify and label each node otherwise you will lose your marks. Mention the units of each derived value.PHY301 Assignment Question no 2:
Use Mesh analysis to find IO in the network given below. Identify and label each mesh otherwise you will lose your marks. Write each step of the calculation to get maximum marks and also mention the units of each derived value.PHY301 Assignment no 2 solution
Here is the Solutions of PHY301 Assignment no 2 :
PHY301 Assignment Question No. 1 Solution:
Solution:V2-V1=6
V2=6+V1
V1-10/4 + V1/2 + Ix = 0
V1-10+2V1+4Ix
3V1+4Ix=10----------------------------------------------------(1)
V2/10-5-Ix=0
V2-50-10Ix=0
V2-10Ix=50-----------------------------------------------------(2)
Adding these two equations
15V1+20Ix=50
2V2-20Ix=100
2V2+15V1=150
2(6+V1)+15V2=150
12+2V1+15V1=150
17V1=138
V1=8.12v
I=V/R
I=8.12/2 I=4.06A
PHY301 Assignment Solution by mujtaba ali kiani.doc, 89 KB
V1-10/4 + V1/2 + Ix = 0
V1-10+2V1+4Ix
3V1+4Ix=10----------------------------------------------------(1)
V2/10-5-Ix=0
V2-50-10Ix=0
V2-10Ix=50-----------------------------------------------------(2)
Adding these two equations
15V1+20Ix=50
2V2-20Ix=100
2V2+15V1=150
2(6+V1)+15V2=150
12+2V1+15V1=150
17V1=138
V1=8.12v
I=V/R
I=8.12/2 I=4.06A
PHY301 Assignment Question No. 2 Solution is Given Below.
You can download PHY301 Assignment no 2 Solution from the links below:PHY301 Assignment Solution by mujtaba ali kiani.doc, 89 KB
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