CS201 Assignment No 1 Spring 2018
Dear Students, Here you can read or Download CS201 - Introduction to Programming Assignment No 1 Solution and Discussion of Semester Spring 2018. Assignment Due Date is 7 MAY, 2018. Total Marks are 20. Lecture covered in this Assignment are from Lec 1 to 6. CS201 Assignment Solution has been added. We are here to facilitate your learning and we do not appreciate the idea of copying or replicating solutions. Previously we shared CS201 Assignment No 1 Solution Fall 2017.CS201 Assignment No 1 Solution Spring 2018 |
Recommended : CS201 Current and Past Mid Term Papers Spring 2017
CS201 Assignment Instructions
Please read the following instructions carefully before submitting assignment:It should be clear that your assignment will not get any credit if:
- Assignment is submitted after due date.
- Submitted assignment does not open or file is corrupt.
- Assignment is copied (From internet/students).
Allowed Software to develop Assignment
Dev C++Recommended : DevC++ Installation and Usage Complete Guidelines
CS201 Assignment Objectives:
To enable students to write, compile and execute a program in Dev C++. Moreover to familiarize students with the concepts of:- Variables and operators
- Expressions in C++
- Decision structures
- Repetition structures
- Break and Continue statements
Assignment Submission Instructions
- You have to submit only .cpp file on the Assignments interface of CS201 at VULMS.
- Assignment submitted in any other format will not be accepted and will be graded zero marks.
CS201 Assignment Question
Write a Program which allows the user to input an integer value for a variable name Limit.
Based on the input value, the program should perform the following tasks:
if user enters Limit=21
Numbers which is divisible by both 3 and 5 is = 15
Numbers which are divisible by either 3 or 5= 3,5,6,9,10,12,18,20,21 (as 15 divisible by both 3 and 5, so it is not included)
Sum will be = 3+5+6+9+10+12+18+20+21= 104
Recommended : C++ Programming Tutorials for Beginners
- Check whether the value entered by the user falls within the range from 10 to 150. (10 and 150 included in the given range.)
- Display those numbers which are divisible by both 3 and 5 in the range from 1 up to the Limit.
- Calculate and display the sum of those numbers which are divisible by either 3 or 5.
- Final task will be to count and display those numbers which are not divisible by 3 or 5.
if user enters Limit=21
Numbers which is divisible by both 3 and 5 is = 15
Numbers which are divisible by either 3 or 5= 3,5,6,9,10,12,18,20,21 (as 15 divisible by both 3 and 5, so it is not included)
Sum will be = 3+5+6+9+10+12+18+20+21= 104
CS201 assignment No 1 Spring 2018 Sample output |
CS201 Assignment Deadline:
The deadline to submit your assignment solution is 7th May, 2018. Your assignment must be submitted within the due date through VULMS. No assignment will be accepted through email after the due date.Recommended : C++ Programming Tutorials for Beginners
CS201 Assignment Solution Sample Preview
You can see the Sample Solution File Page Preview below. and You can easily Download CS201 Assignment Solution File from the Download Button given below:
Solution Code Preview:
#include<iostream>
using namespace std;
int main()
{
int limit, sum=0, count=0;
cout<<"Enter the limit in the range <10 ... 150>: ";
cin>>limit;
if (limit>=10)
{
if(limit<=150)
{
cout<<"Numbers which are divisible by both 3 and 5 is: ";
for(int i=1; i<=limit; i++)
{
if(i%3==0 && i%5==0)
{
cout<<i<<" ";
}
}
for(int i=1; i<=limit; i++)
{
if((i%3==0 || i%5==0) && !(i%3==0 && i%5==0))
{
sum =sum + i;
}
}
cout<<"\nCalculated sum: "<<sum;
for(int i=1; i<=limit; i++)
{
if(i%3!=0 && i%5!=0)
{
count++;
}
}
cout<<"\nTotal Numbers which are not divisible by either 3 or 5 is: "<<count<<endl;
}
else
{
cout<<"Wrong input!! Limit shoud not be greater than 150"<<endl;
}
}
else
{
cout<<"Wrong input!! Limit shoud not be less than 10"<<endl;
}
system("pause");
}
CS201 Assignment Solution Download Link
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mjy cs201 ki 1st assignment chahiye aj last date h koi send ke dy
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